• Perl

my $n = 25;
my $m = 16;

my $a = [ 0..$n-1 ];            # create list reference

sub foo  {
    my ($aref, @idx) = @_;      # unpack sub arguments
    foreach my $i ( @idx ) {
        $aref->[$i] = 42;       # dereference element using ->
    }
}

my @subarray;                   # create list
for ( my $i=0; $i < $m; $i += 2 ) {
    push @subarray, $a->[$i];   # dereference element using ->
}

foo($a, @subarray);             # pass list reference and list

print join ', ', @{ $a };       # deref

• Perl

$n=25;
$m=15;

$A[$n-1] = undef;         # autovivify @A to length $n

sub foo  {
    my ($aref, @i) = @_;
    @$aref[@i] = (42) x @i;
    return;
}

foo(\@A, grep { 0 == $_ % 2 } 0 .. $m);

use Data::Dumper;
print Dumper(@A);

• C#

void Foo(out int element)
{
    element = 42;
}

for (int i = 0; i < m; i += 2)
{
    Foo(out a[i]);
}

• D

void foo(Range)(Range r) {
	r.fill(42);
}

foo(a.indexed(iota(0,m,2)));

• Dart

var a = List.filled(n,0);
foo(a.take(m).toList());
foo(List<int> a) {
  a.fillRange(0, a.length, 42);
}

• Fortran

! Caller:
  integer, dimension(n) :: a
  call foo(a(1:m:2))

! Callee:

  subroutine foo(a)
    integer, dimension(:), intent(inout) :: a
    a = 42
  end subroutine foo

• Go

func foo(a []int, m int) {
	n := len(a)
	for i := 0; i < m && i < n; i += 2 {
		a[i] = 42
	}
}

• Java

interface F { void set(int a[], int m); }
F f = (a, m) -> {
    for (int i = 1; i <= m; a[i] = 42, i = i + 2);
};

• Java

void foo(int a[], int m) {
    for (int i = 1; i <= m; a[i] = 42, i = i + 2);
}

• Kotlin

fun foo(a : IntArray, idx: IntProgression) = 
  idx.forEach{ a[it] = 42 }
foo(a, 0 .. (m-1) step 2)

• Pascal

procedure foo(var L: Integer);
begin
  L := 42;
end;

begin
  for i := 0 to Min(m, n-1) do
    if not odd(i) then foo(a[i]);
end.

• Python

def foo(data, r):
    for i in r: 
        data[i] = 42

foo(a, range(0, m+1, 2))

• Python

def foo(m):
    if m % 2:
        m += 1
    a[:m:2] = [42] * (m // 2)

• Ruby

# @param a [Array<Integer>]
# 
# @return [Array<Integer>]
# 
def foo(a)
  a.fill(42)
end

foo(arry.select(&:odd?))

# For older versions of ruby:
# foo(arry.select { |x| x.odd? })

• Rust

fn foo(el: &mut i32) {
    *el = 42;
}
a.iter_mut().take(m).step_by(2).for_each(foo);

• VB

Sub Foo(ByRef element As Integer)
    element = 42
End Sub

' Statements in caller:
For i = 0 To m - 1 Step 2
    Foo(a(i))
Next