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Programming-Idioms

# 274 Remove all white space characters
Create the string t from the string s, removing all the spaces, newlines, tabulations, etc.
New implementation

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Other implementations 
#include <iostream>
#include <string>
#include <algorithm>
auto t = s;
t.erase(std::ranges::remove_if(t, [](const char c) { return std::isspace(c); }).begin(),t.end()) ;
using System;
using System.Linq;
var t = new string(s.Where(c => !Char.IsWhiteSpace(c)).ToArray());
[Ch || Ch <- "This is a\tstring with\nwhite\rspaces", Ch /= 8, Ch /= 9, Ch /= 10, Ch /= 13, Ch /= 32 ].
import "strings"
import "unicode"
t := strings.Map(func(r rune) rune {
	if unicode.IsSpace(r) {
		return -1
	}
	return r
}, s)
import Data.Char (isSpace)
t = filter (not . isSpace) s
let t = s.replace(/\s/g,'');
String t = s.replaceAll("\\s+", "");
import static java.lang.Character.isWhitespace;
String t = "";
for (char c : s.toCharArray())
    if (!isWhitespace(c)) t = t + c;
String t = "";
for (char c : s.toCharArray())
    switch (c) {
        case ' ', '\t', '\n', '\r' -> {}
        default -> t = t + c;
    }
import static java.lang.Character.isWhitespace;
import static java.lang.String.valueOf;
import static java.util.stream.Collectors.joining;
String t = s.chars()
    .filter(c -> !isWhitespace(c))
    .mapToObj(c -> valueOf((char) c))
    .collect(joining());
(defun remove-whitespace (s &aux |t|)
  "Return a copy of S (a sequence) excluding all the characters space, tab, linefeed, return, and formfeed."
  (setf |t|
    (remove-if
        (lambda (item) (find item '(#\Space #\Tab #\Linefeed #\Return #\Page)))
        s))
  |t|)
  SetLength(t, Length(s));
  i := 0;
  for Ch in S do
    if (Ch > #32) then
    begin
      Inc(i);
      t[i] := Ch;
    end;
  SetLength(t, i);

uses RegExpr;
t := ReplaceRegExpr('\s', s, '');
my $t = $s;
$t =~ s/\s*//g;

def parse(string):
    if not string:
        return ''
    character, *arg = string
    if not character.isspace():
        return character + parse(arg)
    return parse(arg)
t = parse(s)
import re
t = re.sub('\\s', '', s)
t = ''.join(s.split())
from string import whitespace
t = ''
for character in s:
    if character not in whitespace:
        t += character
t = s.gsub(/[[:space:]]/, "")
t = s.gsub(/\s/, "")
let t: String = s.chars().filter(|c| !c.is_whitespace()).collect();

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